50=5x^2-4

Solution for 50=5x^2-4 equation:

50=5x^2-4

We move all terms to the left:

50-(5x^2-4)=0

We get rid of parentheses

-5x^2+4+50=0

We add all the numbers together, and all the variables

-5x^2+54=0

a = -5; b = 0; c = +54;
Δ = b2-4ac
Δ = 02-4·(-5)·54
Δ = 1080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1080}=\sqrt{36*30}=\sqrt{36}*\sqrt{30}=6\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{30}}{2*-5}=\frac{0-6\sqrt{30}}{-10}
=-\frac{6\sqrt{30}}{-10}
=-\frac{3\sqrt{30}}{-5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{30}}{2*-5}=\frac{0+6\sqrt{30}}{-10}
=\frac{6\sqrt{30}}{-10}
=\frac{3\sqrt{30}}{-5}
$